4u^2=11u=3

Solution for 4u^2=11u=3 equation:

4u^2=11u=3

We move all terms to the left:

4u^2-(11u)=0

a = 4; b = -11; c = 0;
Δ = b2-4ac
Δ = -112-4·4·0
Δ = 121
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$u_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$u_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{121}=11$
$u_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-11)-11}{2*4}=\frac{0}{8}
=0
$
$u_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-11)+11}{2*4}=\frac{22}{8}
=2+3/4
$